【印刷可能】 (x^2+y^2-1)^3=x^2y^3 meaning 151773-(x^2+y^2-1)^3=x^2y^3 meaning
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(x^2+y^2-1)^3=x^2y^3 meaning
(x^2+y^2-1)^3=x^2y^3 meaning-Answer Let f(x,y) = c (c is a constant) be the solution This gives df= df/dx dx df/dy dy=0 Here all are partial derivatives Compare this with the main equation (x^3y^3x^2y^2xy1) ydx (x^3y^3x^2y^2xy1) xdy=0 You get df/dx = (x^3y^3x^2y^2xy1) ydx Integrate it1 Answer Sorted by 4 The solution set is obviously symmetric with respect to the y axis Therefore we may assume x ≥ 0 In the domain { ( x, y) ∈ R 2 x ≥ 0 } the equation is equivalent with x 2 y 2 − 1 = x 2 / 3 y , which can easily be solved for y
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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicAlgebra Simplify ( (3x^ (3/2)y^3)/ (x^2y^ (1/2)))^2 ( 3x3 2 y3 x2y−1 2)−2 ( 3 x 3 2 y 3 x 2 y 1 2) 2 Move x3 2 x 3 2 to the denominator using the negative exponent rule bn = 1 b−n b n = 1 b n ( 3y3 x2y−1 2x−3 2)−2 ( 3 y 3 x 2 y 1 2 x 3 2) 2 Multiply x2 x 2 by x−3 2 xAlgebra Graph x^2y^2=1 x2 y2 = 1 x 2 y 2 = 1 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h h represents the xoffset
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